How do you find perimeter of a triangle with 1 side given the angles are 105, 45, and 30 and the only side given is 8, opposite of the angle 30?

Perimeter: ##34.76852## (to the limit of my calculator)
Let ##a## be the length of the side opposite the ##45^@## angle
and ##b## the length of the side opposite the ##105^@## angle.
tells us
##color(white)(“XXX”)8/sin(30^@)=a/sin(45^@)=b/sin(105^@)##
##sin(30^@)=0.5##
##sin(45^@)=0.707107## (approx.)
##sin(105^@)=0.965926## (approx.)
##8/sin(30^@)=16##
##a=16xxsin(45^@)=11.31371##
##b=16xxsin(105^@)=15.45481##
##”Perimeter” = 8 + a + b##
##color(white)(“XXXXX”)=34.76852##