How do you simplify the expression ##(sinx-cosx)/(sinxcosx)##?
February 20th, 2023
##frac{sinx-cosx}{sinx cosx} = secx – cscx##
##frac{sinx-cosx}{sinx cosx} = frac{sinx}{sinx cosx} – frac{cosx}{sinx cosx}##
##= frac{1}{cosx} – frac{1}{sinx}##
##= secx – cscx##