How do you solve ##4times 8*2^{2}##?
February 20th, 2023
##4xx8*2^2=128##
We can use PEMDAS, we should first start with Parentheses (none here), then , Multiplication, Division, Addition and Subtraction (last three too are not applicable here).
Hence ##4xx8*2^2##
= ##4xx8*4##
= ##4xx32##
= ##128##