Posted: July 8th, 2022


Complete “Practice Exercise 11” (page 156) and “Practice Exercise 11” (page 180) in the textbook. For the data set listed, use Excel to extract the mean and standard deviation for the sample of lengths of stay for cardiac patients. Use the following Excel steps:

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1) Enter the data set into Excel.

2) Click on the Data tab at the top.

3) Highlight your data set with your mouse.

4) Click on the Data Analysis tab at the top right.

5) Click on Descriptive Statistics in the analysis tool list.

6) Find the mean and standard deviation of the data sets (for both exercises)

7) Include your analysis of the description of the data set in the excel document.


Question 11 page 156

Suppose that a health plan asserts that a patient hospitalized with coronary heart disease requires no more than 6.5 days of hospital care. However, we believe that a stay of 6.5 days is too low. To examine the claim of the health plan, assume further that we collected data depicting the lengths of stay of 40 patients who were hospitalized recently with coronary heart disease. The results of the sample are as follows :

5, 8, 9, 12, 7, 9, 10, 11, 4, 7,

 8, 5, 8, 13, 11, 10, 6, 5, 8, 9,

5, 12, 7, 9, 4, 8, 7, 7, 11, 5,

 8, 10, 5, 8, 2, 11, 3, 6, 8, 7


If α = 0.05, Use these data to evaluate the claim by the health plan. (MUST INCLUDE IF YOU THINK 6.5 DAYS IS ENOUGH AND WHY. SIMPLY WRITE A SMALL PARAGRAPH EXCEL!)


Question 11 page 180


Suppose that the medical staff indicated that the results of a given laboratory procedure must be available 30 min after the physician submits a request for the service. In this situation, if the results arrived 30 min or less after the request, we regard the performance of the laboratory as timely. If results arrived more that 30 minutes after the request, we regard the performance as tardy. Focusing on the day, evening, and night shifts, suppose that we selected a random sample and obtained the following results. If α = 0.05  Test the proposition that the performance of the laboratory is independent of shift. (MUST INCLUDE THIS IN YOUR ANSWER BY WRITING A SMALL PARAGRAPH!)
















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