How do you evaluate the integral of absolute value of (x – 5) from 0 to 10 by finding area?

Using integrals:
Since the |x-5| is equal to a positive value when x ranges from 5 to 10 but equal to a negative value from 0 to 5, we have to split the integral into two parts. Notice in the previous answer how the graph creates two triangles.
Here’s what we have: ##int_0^5- (x-5) dx## + ##int_5^10 (x-5) dx##
When you integrate using your you obtain:
##-1/2 x^2 + 5x## from 0 to 5 + ##1/2 x^2 – 5x## from 5 to 10.
Substituting upper bound minus lower bound for the first integral results in ##[-1/2(25)+5(5)] – [-1/2 (0) +5(0)]## which equals ##25/2##.
Doing the same for the second integral gives us ##[1/2(100)-5(10)] – [1/2(25)-5(5)]## which equals ##25/2##.
Add the two integral values for the total area: ##25/2+25/2=25##
Hope this helps.