A sock drawer has 8 blue socks and 6 black socks. If I randomly select two socks, one at a time, what is the probability l will first get a blue sock and then, without replacing it, a black sock?

##24/91##
Calculate first the total number of permutation possible.
You select two socks so that will be:
##14*13=182##
Now you must first select a blue sock then a black sock:
You can only pick ##8## possible blue socks
You can only pick ##6## possible black socks
which means that this permutation ##(“blue”->”black”)## have ##8*6=48## possibilities for each different blue and black sock.
express in fraction:
##48/182=24/91##
in case your curious, all possibilities have the following odds:
##(“blue”->”blue”)=56/182=28/91##
##(“black”->”black”)=30/182=15/91##
##(“black”->”blue”)=48/182=24/91##
##(24+24+15+28)/91=91/91##