Explain the use of preparing standard solutions and titrations?

You use a standard solution to determine the concentration of the analyte during a titration.
A standard solution is a solution containing a precisely known concentration of a primary standard.
A primary standard should be a solid with a known formula and a purity of 99.98 %. It must also be stable in air and water-soluble.
Sodium carbonate is a common primary standard base. It is used to prepare standard for the titration of acids.
EXAMPLE
Sodium carbonate (13.25 g) was dissolved in about 150 mL of deionized water in a beaker. The solution was transferred with appropriate washings into a 250 mL volumetric flask. The volume of water was made up to the mark, and the solution was thoroughly shaken to ensure complete mixing.
A 25.00 mL volume of the sodium carbonate solution was pipetted into a conical flask. Methyl orange indicator was added.
The sample required 24.65 mL of a hydrochloric acid solution to completely neutralize it.
Calculate the of the hydrochloric acid.
Solution
Step 1. Calculate the moles of Na₂CO₃.
Moles of Na₂CO₃ = 13.25 g Na₂CO₃ × ##(1″mol Na₂CO₃”)/(105.99″g Na₂CO₃”)## = 0.125 01 mol Na₂CO₃ (4 + 1 guard digit)
Step 2. Calculate the molarity of the Na₂CO₃ solution.
Molarity = ##”moles”/”litres” = (0.125 01″mol”)/(0.2500″L”)## = 0.500 05 mol/L
Step 3. Calculate the moles of Na₂CO₃ in the aliquot.
Moles of Na₂CO₃ = 0.02500 L soln × ##(0.500 05″mol Na₂CO₃”)/(1″L soln”)## = 0.012 501 mol Na₂CO₃
Step 4. Write the balanced chemical equation for the reaction.
Na₂CO₃ + 2HCl → 2NaCl + H₂CO₃
Step 5. Calculate the moles of HCl.
Moles of HCl = 0.012 501 mol Na₂CO₃ × ##(2″mol HCl”)/(1″mol Na₂CO₃”)## = 0.025 002 mol HCl
Step 6. Calculate the molarity of the HCl.
Molarity = ##”moles”/”litres” = (0.025 002″mol”)/(0.024 65″L”)## = 1.014 mol/L