How can I draw and identify the chiral centers of galactose?

The easiest way is to draw galactose as a Fischer projection.
Galactose is an aldohexose. The general formula is HOCH₂(CHOH)₄CHO.
It has four chiral centres: the C atoms in the CHOH groups.
Since there are 4 chiral centres, there are##2^4 = 16## stereoisomers. We can limit ourselves to the 8 D isomers. The other 8 isomers are their L .
How can we reproduce this diagram and identify D-galactose?
Step 1. Draw 8 skeleton Fischer projections, with horizontal crosses at C-2 to C-5.
Step 2. On C-5, draw all OH groups on the right.
Step 3. On C-4, draw OH groups to the right on the first four structures and to the left on the next four.
Step 4. On C-3, draw OH groups in the order 2 to the right, 2 to the left, 2 to the right, 2 to the left.
Step 5. On C-2, alternate the OH groups right, left, right, left, etc.
Step 6. Assign names to the structures using the mnemonic
##”All”## ##”altr”##uists ##”gl”##adly ##”ma”##ke ##”gu”##m ##”i”##n ##”gal”##lon ##”ta”##nks.
##”All”##ose ##”altr”##ose ##”gl”##ucose ##”ma”##nnose ##”gu”##lose ##”i”##dose ##”gal”##actose ##”ta”##lose
So galactose is the second structure from the right.
The chiral centres are at C-2, C-3, C-4, and C-5.
The order of OH groups from bottom to top in galactose is R-L-L-R.

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