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How do you convert ##r=sin(2theta)## into a cartesian equation?

Author:
February 20th, 2023

##x^2 +y^2 =2##
##r = sin (2theta)##
##r = 2sin theta cos theta##
##r = 2(y/r) (x/r) implies r^2 = 2 implies x^2 +y^2 =2##
So it’s a circle with radius ##sqrt(2)##.

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