How do you convert (x-3)squared +(y+4)squared =25 to a polar equation?

##r=2(3 cos theta – 4 sin theta )##. Graph is inserted.
The conversion formula is
##(x, y)=r(cos theta, sin theta)##
So, the polar equation is
(r cos theta- 3 )^2+(r sin theta + 4 )^2=25.
Expanding and simplifying,
##r=2(3 cos theta – 4 sin theta )##
The circle passes through the pole (r = 0 ) ,
when ##theta =tan^(-1)(3/4)=36.87^o## and also when theta =
216.87^o.
This interpretation of reaching the pole is important, in the polar
frame. This discloses the directions of entry into, and exit from, the
pole.
graph{(x-3)^2+(y+4)^2-25=0 [-20, 20, -10, 10]}