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How do you find the derivative of ##(cot^(2)x)##?

Author:
February 20th, 2023

##-2″cosec”^2 x. cotx##
##f(x) = cot^2x##
##d [f(x)]/dx = 2cot x.(-“cosec”^2x).1##
##= -2″cosec”^2 x. cotx##
first you get the derivative of the indice, then the trig function, lastly the x.
it’s easy if you remember it that way 😉

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