How do you solve by completing the square: ##2x^2 + 4x +1 = 0##?
February 20th, 2023
In order to complete the square, add +1 to both sides of the equation:
##2x^2 + 4x + 1 +1 = 0 + 1##;
##2x^2+4x+2=1##;
##2(x^2+2x+1) = 1##;
##x^2+2x+1=1/2##;
##(x+1)^2 = 1/2##;
##x+1 = +-sqrt(1/2) = +-sqrt2 /2##;
Therefore, the answer is :
##x=-1+-sqrt2/2##
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