How do you solve for y in ##x-2y=1 ##?
February 20th, 2023
##color(green)(y =( x- 1)/2 ##
##x-color(blue)(2y)=1##
Since we need to solve for ##y## we need to isolate the term containing ##y##:
##x- 1 = color(blue)(2y)##
##color(green)(2)y = x- 1 ##
##y = (x- 1)/color(green)(2) ##
##y =( x- 1)/2 ##