How would you calculate the number of grams of sodium oxide, Na2O, that will be produced when 5.00 moles react with oxygen given the reaction: 4Na + O2–> 2 Na2O?
February 20th, 2023
##4Na + O_2 rarr 2Na_2O##.
By the of this reaction if 5 mol natrium react, then 2.5 mol ##Na_2O## should result.
The molecular mass of natrium oxide is ##61.98## ##g*mol^(-1)##. If ##5## ##mol## natrium react, then ##5/2## ##molxx61.98## ##g*mol^(-1)## ##=## ##154.95## ##g## natrium oxide should result.
So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.