The Eiffel Tower in Paris stands 300.0 m tall on a day of average temperature, 22.0°C. How much taller is the steel tower on a hot summer day (T = 40°C) in centimeters? (αsteel = 11 x 10-6 °C-1)

Let’s use the GRASS method to solve this problem.
Given:
Original length ##(L_o)## = 300.0 m
Coefficient of Linear expansion of steel ##(alpha) = 11 times 10^{6 circ}C^-1##
Temperature change ##(Delta T) = 40-22 = 18.0 ^circC##
Required to find: Change in length ##(Delta L)##
Analysis: The formula for figuring out this question is
##Delta L = alpha L_o Delta T##
The unknown value is already isolated, so we do not need to manipulate the formula.
Solve and Significant Figures:
##Delta L = (11 times 10^6 ^o C^-1) (300.0 m) (18^oC)##
##Delta L = 0.0594 m##
Convert to centimeters by multiplying by 100:
##Delta L = 5.94 cm##
This means the Eiffel Tower is 5.94 cm taller on a hot day of 40 degrees than it is at 22 degrees.