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What is the derivative of ##1+tan^2x##?

Author:
February 20th, 2023

##2tanxsec^2x##
differentiate using the##color(blue)(” chain rule “) ##
rewrite ## tan^2x = (tanx)^2##
##d/dx[ 1 + (tanx)^2] = 2(tanx) d/dx(tanx) ##
## = 2tanxsec^2x ##

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