What is the Integral of ##1/tan(x) dx##?
February 20th, 2023
##lnabs(sinx) +C##
##1/tanx = cotx = cosx/sinx##
With ##u = sinx##, we get
##int1/tanx dx= intcotx dx##
## = int cosx/sinx dx##
Let ##u = sinx##, so ##du = cosx dx## to get
## = int 1/u du##
## = ln absu +C##
## = ln abs sinx +C##
